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A Math Problem (OT)

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jmcquown - 07 Nov 2006 04:45 GMT
This is fun!  A friend sent it to me in email.

1.  Grab a calculator.  (you won't be able to do this one in your head)
2.  Key in the first three digits of your phone number (NOT the country and
area code)
3.  Multiply by 80
4.  Add 1
5.  Multiply by 250
6.  Add the last 4 digits of your phone number
7.  Add the last 4 digits of your phone number again.
8.  Subtract 250
9.  Divide number by 2

Do you recognize the answer?

Jill
christal63 - 07 Nov 2006 09:15 GMT
jmcquown kirjoitti:
> This is fun!  A friend sent it to me in email.
>
[quoted text clipped - 12 lines]
>
> Jill

That was fun. I guess it works as long as you have 7 digits in your
phone number. Most do, but some don't. Some ppl here have 6 digits in
their hard line and ppl with old cell phone numbers can even have a 5
digit number.

Christine in Laitila, posting from work
Yowie - 07 Nov 2006 21:28 GMT
> jmcquown kirjoitti:
>> This is fun!  A friend sent it to me in email.
[quoted text clipped - 19 lines]
> their hard line and ppl with old cell phone numbers can even have a 5
> digit number.

Australian phone numbes are 8 digits long, but yes, it was fun. Thanks!

Yowie
Zzzzzzzz - 08 Nov 2006 08:49 GMT
> Australian phone numbes are 8 digits long, but yes, it was fun.
> Thanks!

For 8 digits, replace step 3 by multiply by 800 (and the other steps instead
of 4 last should be 5 last)
For 6 digits, replace step 3 by multiply by 8. (same remark expect 4 last is
3 last)

(Didn't check it but should work)
Nomen Nescio - 07 Nov 2006 18:10 GMT
-----BEGIN PGP SIGNED MESSAGE-----

From: "jmcquown" <jmcquown@bellsouth.net>

>1.  Grab a calculator.  (you won't be able to do this one in your head)
>2.  Key in the first three digits of your phone number (NOT the country and
[quoted text clipped - 7 lines]
>
>Do you recognize the answer?

I find it sad that "you won't be able to do this one in your head"
No wonder the rest of the world is kickin' our butts in technology
jobs that we are moving overseas.

try it this way:

2. think of the first 3 digits
3a. multiply times 8
 3a.(alternate) You can't multiply a 3 digit number times 8?
 ok. multiply it times 2. (double it)
 double it again.
 double it a third time.
3b. now tack a zero on to the end
4. add 1
5a. Multiply by 25
  5a (alternate) You can't multiply by a 2 digit number?
  ok. divide the number by 4 then move the decimal point 2 spaces
  to the right.
  5a. (alternate to the alternate) divide by 2 then divide by 2 again and
  move the decimal point 2 spaces to the right
5b. move the decimal point another space to the right
(if you can't do 6-9, go back to 4th grade)
6.  Add the last 4 digits of your phone number
7.  Add the last 4 digits of your phone number again.
  6&7(alternate) double the last 4 digits then add that to (2-5) [but this requires
  remembering two numbers, which can be confusing. At least for me it is]
8.  Subtract 250
9.  Divide number by 2

There, you just did it in you head. :)
And if you think about it, it should now be quite obvious why this works.
Victor Martinez - 08 Nov 2006 23:42 GMT
> 1.  Grab a calculator.  (you won't be able to do this one in your head)

Says who? ;-)

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Victor M. Martinez
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Nomen Nescio - 10 Nov 2006 04:50 GMT
-----BEGIN PGP SIGNED MESSAGE-----

From: Victor Martinez <me@nospam.com>

>> 1.  Grab a calculator.  (you won't be able to do this one in your head)
>
>Says who? ;-)

I didn't know you were an engineer. :)
 
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